Do the following base two division problem.

Read the dividend from left to right until you get a number that is larger than the divisor. This happens in the 6th place from the left or the 8th place from the right which would be the onehundred twenty-eight's place. Put a 1 in that place in the quotient and multiply it times the divisor and subtract from the dividend.

Bring down the next digit.

Since the remainder is now bigger than the divisor, put a 1 in the next place in the quotient, multiply times the divisor and subtract again

When we bring down the next digit, the remainder is not yet bigger than the divisor, so we put a 0 in the next place in the quotient

When we bring down the next digit, the remainder is still not bigger than the divisor, so put a 0 in the next place in the quotient.

When we bring down the next digit, the remainder is finally bigger than the divisor, so put a 1 in the next place in the quotient, multiply times the divisor and subtract.

At this point the remainder will never be bigger than the divisor, so fill in all of the remaining places in the quotient with zeroes.

The remainder is 1110.