Theorem 6.3: (The Commutative Property for Addition of Natural Numbers) Let a and b be natural numbers. Then

a + b = b + a

Proof: By Theorem 6.2 we can find two disjoint sets S, and T such that

#(S ) = a

and

#(T ) = b

Then by Theorem 6.1

and

However, by Theorem 2.1, the commutativity of unions of sets,

so by Theorem 5.4, the well definedness of cardinality,

a + b = b + a