### Solution to problem 1

1. Find

when

We have some algebra to do to simplify the right side of this
equation. We are subtracting fraction in the numerator, so we need
common denominators.

We are now ready to invert the bottom and multiply.

When we do, we can reduce the fraction. Our final result is
continuous when h = 0, so the limit is obtained by simply
substituting a 0 in for h.

Note that this gives you the same result we would get if we
applied the power rule to the problem.