5. Express as a single log log_bx - 2 log_by + 3 log_bz

This is the reverse of the last problem. We use the same rules

• logb(xy) = logbx + logby
• logbxr = rlogbx
• logb(x/y) = logbx - logby

backwards.

First use the middle rule to turn all of the coefficients into exponents.

Then we use the first and third rules to get the final answer.